SACC
// navigation
Questions 1
Answers 1
Questions 2
Answers 2
// Questions 1
a+0=
a'*0=
a+a'=
a+a=
a+ab=
a+a'b=
a(a'+b)=
ab+a'b=
(a'+b')(a'+b)=
a(a+b+c)=
// Answers 1
a+0=
a
a'*0=
0
a+a'=
1
a+a=
a
a+ab=
a
a+a'b=
a+b
a(a'+b)=
aa'+ab=ab
ab+a'b=
b(a+a')=b
(a'+b')(a'+b)=
a'a'+a'b+b'a'+b'b=a'+a'b+a'b'=a'(1+b+b')=a'
a(a+b+c)=
aa+ab+ac=a
// Questions 2
f
(a,b,ab)=
f
(a,b,a'b')=
f
(a,b,(ab)')=
y+yy'=
xy+xy'=
x'+yx'=
(w+x'+y+z')y=
(x+y')(x+y)=
w+[w+(wx)]=
x[x+(xy)]=
(x'+x')'=
(x+x')'=
w+(wx'yz)=
w'(wxyz)'=
xz+x'y+zy=
x+z)(x'+y)(z+y)=
x'+y'+xyz'=
// Answers 2
f
(a,b,ab)=
a+b+ab=a+b
f
(a,b,a'b')=
a+b+a'b'=a+b+a'=1
f
(a,b,(ab)')=
a+b+(ab)'=a+b+a'+b'=1
y+yy'=
y
xy+xy'=
x(y+y')=x
x'+yx'=
x'(1+y)=x'
(w+x'+y+z')y=
y
(x+y')(x+y)=
x
w+[w+(wx)]=
w
x[x+(xy)]=
x
(x'+x')'=
x
(x+x')'=
0
w+(wx'yz)=
w(1+x'yz)=w
w'(wxyz)'=
w'
xz+x'y+zy=
xz+x'y
x+z)(x'+y)(z+y)=
(x+z)(x'+y)
x'+y'+xyz'=
x'+y'+z'